Session 2: Independent study with calculations · 180 minutes
16 October 2026
Your action: Read this schedule, then advance. All times are elapsed lesson time, including your calculations.
This lesson replaces the class on 16 October 2026.
| Activity | Minutes | Elapsed |
|---|---|---|
| Preparation and goals | 10 | 0–10 |
| Phase and material-balance checks | 25 | 10–35 |
| From Raoult’s law to liquid nonideality | 30 | 35–65 |
| Antoine conventions | 25 | 65–90 |
| Break | 10 | 90–100 |
| Lab 08 investigation | 45 | 100–145 |
| Review test, corrections, exit and feedback | 35 | 145–180 |
Times include reading and working through calculations. Pause before each solution.
Your action: Open worksheet pages 1–4 and read this slide. Do not start the exercises or Lab yet.
Download the 4-page worksheet. Keep this slide deck and the worksheet open side by side. A calculator and paper are enough until minute 100.
Last lesson: ideal-mixture VLE and phase calculations. Today: how we describe departures from the ideal-liquid prediction.
The 3-page reading is optional background. Skim it if time permits. This deck contains the instructions required for today.
By the end, you should be able to:
Your action: Read this slide only. No worksheet answer is required yet. The next slide starts page 1, Section A.
| Symbol | Meaning |
|---|---|
| zᵢ | Overall mole fraction in the feed |
| xᵢ | Mole fraction in the liquid phase |
| yᵢ | Mole fraction in the vapor phase |
| β = V/F | Fraction of total moles in the vapor phase |
z_i=(1-\beta)x_i+\beta y_i
For each existing phase, its mole fractions sum to one.
Your action: Open worksheet page 1. Complete A1–A3 using this slide and your calculator. No Lab is needed.
Ideal binary mixture at 350 K: z₁=0.5, P₁ˢᵃᵗ=150 kPa, P₂ˢᵃᵗ=60 kPa.
P_{bubble}=\sum_i z_iP_i^{sat},\qquad P_{dew}=\left(\sum_i\frac{z_i}{P_i^{sat}}\right)^{-1}
Finish A1–A3 before advancing to the solution.
Your action: Compare this solution with page 1, A1–A3. Add corrections beside your original answers.
P_{bubble}=0.5(150)+0.5(60)=105\ \mathrm{kPa}
P_{dew}=[0.5/150+0.5/60]^{-1}=85.714\ \mathrm{kPa}
| Pressure | Equilibrium state |
|---|---|
| 80 kPa | Vapor, below the dew boundary |
| 95 kPa | Liquid + vapor, between the boundaries |
| 110 kPa | Liquid, above the bubble boundary |
At 110 kPa, β=0 and x₁=z₁=0.5. No vapor phase exists, so y is undefined.
Your action: On worksheet page 1, complete A4: material balance and composition sums. Stop before the next solution.
At 95 kPa, use x₁=0.388889, y₁=0.614035 and β=0.493506.
Calculate:
z_1=(1-0.493506)(0.388889)+0.493506(0.614035)
Then find x₂ and y₂. Check each phase sum separately.
Use the numbers on this slide. No Lab is required for this calculation.
Your action: Check page 1, A4 against this slide. Keep the substituted balance and correct any mismatch.
z_1\approx0.196970+0.303030=0.500000
x₂=0.611111 and y₂=0.385965.
x_1+x_2=1,\qquad y_1+y_2=1
An incorrect phase sum can reveal a transcription error even when the plotted result looks plausible.
Your action: Read this slide. On scratch paper, calculate 60/48 before advancing. No new worksheet entry is required.
For an ideal liquid mixture with ideal vapor:
y_iP=x_iP_i^{sat}(T)
The liquid mole fraction scales the pure-component vapor pressure.
At x₁=0.4 and P₁ˢᵃᵗ=120 kPa, this predicts a partial pressure of 48 kPa.
Suppose the observation instead gives y₁P=0.6(100)=60 kPa. The ideal-liquid prediction is too low.
Think: what factor would multiply 48 to give 60?
Your action: Read this definition of gamma. Compare 1.25 with your scratch calculation. No Lab or worksheet entry is required.
The factor is 60/48=1.25. We call it the activity coefficient, written γ (gamma).
y_iP=x_i\gamma_iP_i^{sat}(T)
We still assume ideal vapor and negligible Poynting correction. Verify the observations and vapor-pressure inputs before attributing a mismatch to liquid nonideality.
Your action: Read this slide and check 1.25 × 0.4 on your calculator. Keep worksheet B blank until minute 48.
a_i=\gamma_i x_i
Activity aᵢ represents liquid composition adjusted for nonideal behavior. Here the reference is the pure liquid. Both aᵢ and γᵢ are dimensionless.
For an ideal liquid solution, γᵢ=1 and aᵢ=xᵢ.
For x₁=0.4 and γ₁=1.25, a₁=0.50.
Your action: Read the equation and assumptions here. You will use them in worksheet page 1, B1–B3 on the next slide.
Rearrange the modified Raoult equation to estimate gamma from an observation.
With ideal vapor and negligible Poynting correction:
y_iP=x_i\gamma_iP_i^{sat}(T)
\gamma_i=\frac{y_iP}{x_iP_i^{sat}(T)}
Use the same pressure units in P and Pˢᵃᵗ. The inferred γ depends on the vapor-pressure correlation and these assumptions.
Your action: On worksheet page 1, complete B1–B3. Use only the observation on this slide. No Lab is needed.
Synthetic observation: P=100 kPa, x₁=0.4, y₁=0.6.
Show substitution and unit cancellation in B1–B3.
Your action: Check page 1, B1–B3 with this slide. Correct your values and finish the explanation in B3.
| Assumed P₁ˢᵃᵗ | γ₁ = y₁P/(x₁P₁ˢᵃᵗ) | a₁ = γ₁x₁ |
|---|---|---|
| 120 kPa | 60/48 = 1.25 | 0.50 |
| 150 kPa | 60/60 = 1.00 | 0.40 |
The observations stay unchanged. Increasing the assumed vapor pressure lowers the inferred γ.
A fitted model can absorb a property error into its parameters. Check the property source independently.
Now correct your work and write one sentence explaining the difference.
Your action: Read this slide. Open worksheet page 2, C, ready for the next exercise. Do not fill the Lab section D yet.
A common form is:
\log_{10}(P^{sat}/P_{unit})=A-\frac{B}{T_{source}+C}
Before entering constants, identify:
Changing a menu setting does not automatically convert the constants.
Your action: On worksheet page 2, answer C1–C4 using this synthetic correlation. Do not enter these constants in Lab 08.
A synthetic teaching correlation, valid from 20 to 80 °C:
\log_{10}(P^{sat}/\mathrm{kPa})=4-\frac{1000}{T_C+200}
Write the equation and substitutions, not only the answer.
Your action: Check page 2, C1–C4 with this slide. Write corrections and their reasons before taking the break.
4-\frac{1000}{50+200}=0,\qquad P^{sat}=10^0\ \mathrm{kPa}=1\ \mathrm{kPa}
Correct your calculation before moving on.
Your action: Pause for ten minutes. Keep your worksheet. At minute 100, open Lab 08 using the link below.
Take ten minutes away from the screen.
Keep your calculations. Next, you will use the same checks on the synthetic dataset in Lab 08.
Your action: Open Lab 08 and worksheet page 2, D1–D2. Follow the four steps below. Save the baseline JSON before continuing.
In Lab 08:
Record the convention and valid range in D1–D2. Range fields use kelvin. A consistency result marked “not-assessed” or “not-applicable” is not an input error.
Your action: Keep Lab 08 open. Complete page 2, D3 and page 3, E1 for component 1 at the same selected row.
Choose one interior observation from Imported observations.
Write its T, P, x₁ and y₁. The normalized table uses K and kPa.
Complete D3 on page 2 and E1 on page 3.
If values disagree: check component order, units and log base first.
Your action: In Lab 08, use Fit selected model for each model below. Complete worksheet page 3, E2 and save both model exports.
Fit Margules · 1 parameter, then NRTL · fixed α, using α=0.3.
Keep the observations and property inputs unchanged. Leave temperature-dependent parameters off for this comparison.
For each fit, select View: Pressure and vapor residuals. Record:
Export each model’s complete study JSON and fitted residuals CSV before switching models. Give the files distinct names.
Your action: Read this table, then complete worksheet page 3, F using your E2 results. No additional Lab or dataset is required.
| Evidence | What it establishes |
|---|---|
| Solver convergence | The optimizer met its stopping criterion |
| Small training residuals | The model reproduces the fitted observations |
| Consistency diagnostic | Agreement with a thermodynamic constraint under stated assumptions |
| Held-out observations | Evidence about prediction beyond the fitting data |
Complete F on worksheet page 3: state one finding, its numerical evidence and one limitation.
The example data were generated with NRTL. Its close fit is expected model recovery, not evidence of universal superiority. Consistency and prediction require separate checks.
Your action: Open worksheet page 4, Review test. Read these rules before answering. The questions appear on the next two slides.
This is practice with attendance credit. Credit is for completing the activity, rather than a minimum accuracy score.
Work individually. You may consult the lesson and your calculations.
Write answers to the next six questions, then review the solutions. Preserve your original answers and corrections.
The attendance submission route will be provided separately. The anonymous exit/feedback form does not identify attendance.
Your action: Write Q1–Q3 in the matching spaces on worksheet page 4. Show your calculations before advancing.
1. Ideal binary mixture: z₁=0.5, P₁ˢᵃᵗ=160 kPa, P₂ˢᵃᵗ=80 kPa. At P=130 kPa, identify the phase and its composition. Show a boundary calculation.
2. For a separate binary mixture in two-phase equilibrium, x₁=0.3, y₁=0.7 and z₁=0.5. Calculate β by material balance.
3. For P=90 kPa, x₁=0.3, y₁=0.5 and P₁ˢᵃᵗ=100 kPa, calculate γ₁ and a₁. Assume ideal vapor and negligible Poynting correction.
Keep your substitutions and units.
Your action: Write Q4–Q6 on worksheet page 4. For Q6, reuse your page 3, E2 results. Finish before viewing solutions.
4. A synthetic correlation is log₁₀(Pˢᵃᵗ/kPa)=5−1200/(T_C+200), valid at 20–80 °C. Find Pˢᵃᵗ at 40 °C. Can you insert 313.15 directly for T_C?
5. NRTL gives a lower training error than Margules. Does that establish thermodynamic consistency and better prediction? Explain.
6. From your Lab 08 results, report one comparison with its metric and units. State one limitation of your conclusion.
Finish your own answers before opening the next slide.
Your action: Check worksheet page 4, Q1–Q4. Add corrections beside the original answers, using extra paper if needed.
1. P_bubble=0.5(160)+0.5(80)=120 kPa. At 130 kPa the mixture is liquid, x₁=0.5 and β=0.
2. β=(z₁−x₁)/(y₁−x₁)=(0.5−0.3)/(0.7−0.3)=0.5.
3. γ₁=0.5(90)/[0.3(100)]=1.5 and a₁=1.5(0.3)=0.45.
4. 5−1200/(40+200)=0, so Pˢᵃᵗ=1 kPa. Convert 313.15 K to 40 °C first.
Mark any correction beside your original answer.
Your action: Check page 4, Q5–Q6. Explain each correction. Retain all four worksheet pages and the Lab exports for attendance submission.
5. Lower training error alone establishes neither claim. Consistency needs an applicable thermodynamic diagnostic. Prediction needs observations excluded from fitting.
6. A complete answer identifies the same dataset, reports both model results with the metric and units, and gives a defensible limitation.
For example: “Model ___ has lower mean absolute pressure error on this dataset. I have not tested it on excluded observations.” Fill the blank using your own result.
Your action: Open the Session 2 form using the QR code or link. Use page 3, F for reasoning, page 2, C/D for the property check, and E1 for numerical evidence.
5 min: explain and check
Does a small fitting residual establish thermodynamic consistency? Explain and name one independent check of the vapor-pressure inputs. Add one substituted γ or Pˢᵃᵗ calculation.
3 min: feedback on independent learning
Report pace and Lab access. Use the comment box to describe any difficulty with this format.
The form requests no name, ID or email. Wait for “Response received.” Keep attendance work separately.