Solution Thermodynamics

Module 3 · 2105603 Advanced Chemical Engineering Thermodynamics

Soorathep Kheawhom

9 August 2026

 

A partial molar property is not a property of the pure substance.

Mix one litre of ethanol with one litre of water
and you get 1.93 litres.

What this module builds

Introduction

The mixture toolkit, with the rigour Module 1 applied to pure fluids: partial molar properties, fugacity in a mixture, excess properties, activity, and the constraint that ties them together.

The callback

The mixture fugacity coefficient is a composition derivative of the same residual Helmholtz energy Module 1 built. The equation of state is not left behind when mixtures arrive; it is differentiated once more.

Five questions

  • What is a partial molar property, and why is it not a pure-component one?
  • What is \hat f_i, promised at the end of Module 2?
  • What is an excess property measured against?
  • What constraint links \gamma_1 and \gamma_2?
  • What is a model, once you see what G^E is?

Partial molar properties

PART I

Section 3.1   A composition derivative, a tangent construction, and a constraint that returns in Module 4.

The definition, and the Euler relation

3.1 · Partial molar properties

The contribution one species makes to a mixture property, at fixed everything else.

\bar M_i \equiv \left(\frac{\partial (nM)}{\partial n_i}\right)_{T,P,n_{j\ne i}} \qquad\qquad nM = \sum_i n_i \bar M_i \qquad\qquad M = \sum_i x_i \bar M_i

Why T, P and n_j are all fixed

Change any of them and you are measuring something else. The subscripts are not decoration: a derivative at constant T and V is a different quantity with a different value, and the two get confused constantly.

What the Euler relation says

The mixture property is exactly the mole-weighted sum of the partial molar values — with no leftover term. That is not obvious, and it is the reason the partial molar quantity is the right way to apportion a mixture property among its species.

The tangent-intercept construction

3.1 · Partial molar properties

F3.1 · Measured ethanol/water molar volume at 298.15 K. The tangent’s two intercepts are the partial molar volumes.

Partial molar volume can be negative

3.1 · Partial molar properties

The number

At infinite dilution in water, the partial molar volume of ethanol falls about 11 % below its pure molar volume, and water’s falls about 21 % below its own. Adding a mole of ethanol to a large volume of water adds less volume than a mole of pure ethanol occupies.

Why

Water’s hydrogen-bonded network has voids. A small solute can sit in them, so the mixture takes up less room than the sum of the parts. In systems with stronger effects — an electrolyte in water — the partial molar volume of the salt is genuinely negative.

F3.2 · From the same measured data, differentiated. The infinite-dilution values are extrapolations and the figure marks the region where no data exist.

Gibbs-Duhem, in full

3.1 · Partial molar properties

Write it with all its terms before dropping any, because the dropped ones come back in Module 4.

\left(\frac{\partial M}{\partial T}\right)_{P,x}{\rm d}T + \left(\frac{\partial M}{\partial P}\right)_{T,x}{\rm d}P - \sum_i x_i\,{\rm d}\bar M_i = 0

\xrightarrow[\ \text{constant } T,\,P\ ]{}\qquad \sum_i x_i\,{\rm d}\bar M_i = 0

What it means

The partial molar properties of a mixture are not independent functions of composition. Specify one across the range and the other is determined. This is a constraint imposed by thermodynamics, not a modelling convenience.

The dropped terms

Constant T and P is the usual specialisation and it is the one every textbook uses. Isobaric VLE data are not at constant T, so the temperature term survives — as an excess enthalpy contribution that most published consistency tests quietly drop. Module 4 quantifies it.

Fugacity in a mixture

PART II

Section 3.2   The composition derivative promised at the end of Module 2.

Chemical potential is a partial molar property

3.2 · Chemical potential and fugacity in a mixture

Nothing mysterious. It is the partial molar Gibbs energy, and it inherits every property partial molar quantities have.

\mu_i \equiv \left(\frac{\partial (nG)}{\partial n_i}\right)_{T,P,n_{j\ne i}} = \bar G_i

\hat f_i \ \text{ defined by }\ {\rm d}\mu_i = RT\,{\rm d}\ln \hat f_i \qquad\qquad \hat\varphi_i = \frac{\hat f_i}{y_i P}

The pattern repeats

Module 2 defined f so that {\rm d}\mu = RT\,{\rm d}\ln f held for a pure fluid. The mixture definition is the same construction applied to \mu_i, with \hat f_i / (y_i P) \to 1 as P \to 0 fixing the constant.

Where Gibbs-Duhem bites

Because \mu_i is a partial molar property, \sum_i x_i\,{\rm d}\mu_i = 0 at constant T and P — and therefore \sum_i x_i\,{\rm d}\ln\hat f_i = 0. The constraint is inherited, not added.

From the equation of state, again

3.2 · Chemical potential and fugacity in a mixture

\ln\hat\varphi_i is the composition derivative of the residual property Module 1 built. The equation of state carries straight into mixtures.

\ln\hat\varphi_i = \frac{1}{RT}\int_\infty^{V}\! \left[\left(\frac{\partial P}{\partial n_i}\right)_{T,V,n_{j}} - \frac{RT}{V}\right]{\rm d}V \; - \ln Z

For Peng-Robinson

With the van der Waals one-fluid rule a = \sum_i\sum_j x_ix_j\sqrt{a_ia_j}(1-k_{ij}) and b = \sum_i x_i b_i, the integral closes and gives a formula of the same shape as the pure-component one plus two composition-derivative terms — \bar b_i/b and \sum_j x_j a_{ij}/a.

Why this matters later

This is the \hat\varphi_i that appears in the gamma-phi equation of Module 4, in the phi-phi route of Module 5, and in K_\varphi in Module 6. It is computed once and used in three later modules.

The ideal solution is a model

3.2 · Chemical potential and fugacity in a mixture

The Lewis-Randall rule is an assumption about behaviour, not a definition. Saying so now prevents a lot of confusion in Module 4.

\hat f_i^{\,\rm id} = x_i f_i \qquad\qquad \bar M_i^{\,\rm id} = M_i \ \ \text{for } V \text{ and } U, \qquad \bar G_i^{\,\rm id} = G_i + RT\ln x_i

What it assumes

That a molecule of i sees the same environment in the mixture as in pure i. True when the species are chemically almost identical — benzene and toluene — and false the moment hydrogen bonding or a size disparity enters.

Why the entropy term survives

Even an ideal solution has \bar G_i \ne G_i: there is an entropy of mixing whatever the interactions are. Ideality is a statement about energies, not about entropy — which is why \Delta g_{\rm mix} never vanishes and why Module 5’s stability argument has an ideal part that always favours mixing.

Excess properties and activity

PART III

Section 3.3   Departure from an ideal solution, and the reference state that decides the number.

Excess, and why the reference is a solution

3.3 · Excess properties, activity and the reference state

A residual property is measured against an ideal gas. An excess property is measured against an ideal solution. Different baselines, different questions.

M^E \equiv M - M^{\,\rm id} \qquad\qquad a_i \equiv \frac{\hat f_i}{f_i^{\,\circ}} \qquad\qquad \gamma_i \equiv \frac{a_i}{x_i} = \frac{\hat f_i}{x_i f_i^{\,\circ}}

Why not an ideal gas

Because the departure of a liquid from an ideal gas is enormous and almost entirely uninteresting — it is dominated by condensation, which is a pure-component effect. The departure from an ideal solution isolates what mixing did.

The central identity

\frac{G^E}{RT} = \sum_i x_i \ln\gamma_i

and \ln\gamma_i is the partial molar quantity of G^E/RT. Everything in Modules 4 and 5 rests on that one line.

Which terms dominate, and when

3.3 · Excess properties, activity and the reference state

F3.3 · G^E = H^E - TS^E at two temperatures. H^E here is a model derivative, not a calorimeter reading — the figure says so.

Lewis-Randall against Henry

3.3 · Excess properties, activity and the reference state

The same physical system gives different numerical \gamma under the two conventions. Two papers can disagree without either being wrong.

Lewis-Randall

f_i^{\,\circ} = f_i, the pure liquid, so \gamma_i \to 1 as x_i \to 1.

Natural for a solvent, or for components of comparable amount. The convention used throughout Modules 4 and 5.

Henry

f_i^{\,\circ} = \mathcal{H}_i, the Henry constant, so \gamma_i^* \to 1 as x_i \to 0.

Natural for a dissolved gas or a solute that never approaches purity — and essential when the pure liquid does not exist at those conditions.

\gamma_i^* = \gamma_i / \gamma_i^\infty. The conversion is one division, and the number changes by whatever \gamma_i^\infty happens to be — often a factor of five or more. A \gamma without its convention is not a number.

Gibbs-Duhem as a constraint

PART IV

Section 3.4   \gamma_1 and \gamma_2 are not independent functions. Fitting them separately is not allowed.

The binary form

3.4 · Gibbs-Duhem as a constraint on activity coefficients

\sum_i x_i\,{\rm d}\ln\gamma_i = 0 \qquad\Longrightarrow\qquad x_1 \frac{{\rm d}\ln\gamma_1}{{\rm d}x_1} + x_2 \frac{{\rm d}\ln\gamma_2}{{\rm d}x_1} = 0

Opposite signs, fixed ratio

Wherever one curve rises the other must fall, and the slopes stand in the ratio -x_2/x_1. Not approximately — exactly, at every composition.

At the ends

As x_1 \to 1, {\rm d}\ln\gamma_1/{\rm d}x_1 \to 0: the curve for the abundant component must flatten. A fitted \gamma_1 with a finite slope at x_1 = 1 is not admissible, whatever its residual.

The consequence

Fitting \ln\gamma_1 and \ln\gamma_2 as two independent functions produces a pair that thermodynamics forbids. Fitting one G^E and differentiating it cannot — which is the whole reason models are written as G^E.

The constraint, drawn

3.4 · Gibbs-Duhem as a constraint on activity coefficients

F3.4 · Paired tangents at four compositions. The slope ratio equals -x_2/x_1 at every one.

Models are choices of G^E

PART V

Section 3.5   Once you see that, the list of models stops being a list to memorise.

One expansion, several special cases

3.5 · Models as choices of excess Gibbs energy

Redlich-Kister is the general polynomial truncation. Margules and van Laar fall out of it.

\frac{G^E}{RT} = x_1x_2\left[A + B(x_1-x_2) + C(x_1-x_2)^2 + \cdots\right]

B = C = 0

Two-suffix Margules. One parameter, symmetric, and structurally unable to skew.

C = 0

Three-suffix Margules. Two parameters, and \ln(\gamma_1/\gamma_2) becomes quadratic in x_1 - x_2 — which is enough to produce a double azeotrope, a thing often wrongly said to need three.

van Laar

Not a truncation but a ratio of polynomials. Two parameters, and its \ln(\gamma_1/\gamma_2) has exactly one interior zero for same-sign parameters — so it cannot produce a double azeotrope, whatever the fit.

Local composition models

3.5 · Models as choices of excess Gibbs energy

State the physical assumption behind each, not only the algebra.

Wilson

The composition around a molecule differs from the bulk composition, Boltzmann-weighted by interaction energy. Two parameters, good temperature behaviour, and structurally incapable of liquid-liquid equilibrium.

NRTL

The same local-composition idea plus a non-randomness parameter \alpha, which gives the model a second length scale. Two fitted parameters with \alpha usually fixed at 0.3 — and it can produce a phase split.

UNIQUAC

Splits G^E into a combinatorial part from molecular size and shape — fixed by r and q, which are not fitted — and a residual part carrying the two adjustable energies. Extrapolates in composition better for that reason.

UNIFAC is UNIQUAC with the residual parameters estimated from functional groups instead of fitted. That makes it predictive — usable with no data at all — and correspondingly less accurate than a fit to your own measurements.

Four models, one dataset

3.5 · Models as choices of excess Gibbs energy

F3.5 · The same G^E fitted four ways. On the upper axis the curves are indistinguishable; the residual panel is where the differences live.

What each model can and cannot do

3.5 · Models as choices of excess Gibbs energy

F3.6 · Every claim in the table is either derivable from the functional form or verified by a sweep run for this figure.

What you must be able to do

Closing

The module in six statements.

  1. Define a partial molar property and explain, with the ethanol/water number, why it is not a property of the pure substance.
  2. Use the tangent-intercept construction and say what it is computing.
  3. Write Gibbs-Duhem in full and name the term that is dropped at constant T and P — and where it returns.
  4. Get \hat\varphi_i from an equation of state and recognise it as a composition derivative of Module 1’s residual property.
  5. State a reference state whenever you state a \gamma. Lewis-Randall or Henry, and the conversion between them.
  6. Read a model as a choice of G^E and say what its functional form can and cannot represent.